One more <<proof>> of Helen Mironchick's axiom - there is no such system of equations in Boolean variables that could not be solved via the mapping method
Actually we have the system
(x1⊕x2)^(x1=>y1) =1
(x2⊕x3)^(x2=>y2) =1
(x3⊕x4)^(x3=>y3) =1
. . . . . . . . . . . . . .
(x6⊕x7)^(x6=>y6) =1
x7=>y7 =1
Solution via technique 08/2016 (Helen Mironchick)
References
1. http://kpolyakov.spb.ru/download/mea-2016-8.pdf
(x1⊕x2)^(x1=>y1) =1
(x2⊕x3)^(x2=>y2) =1
(x3⊕x4)^(x3=>y3) =1
. . . . . . . . . . . . . .
(x6⊕x7)^(x6=>y6) =1
x7=>y7 =1
Solution via technique 08/2016 (Helen Mironchick)
References
1. http://kpolyakov.spb.ru/download/mea-2016-8.pdf


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