Original System
(x1=>x2)^(x2⊕x3)^(x3=>x4)^(x4=>x5)^(x5=>x6)=1
(y1=>y2)^(y2=>y3)^(y3⊕y4)^(y4=>y5)^(y5=>y6)=1
(z1=>z2)^(z2=>z3)^(z3=>z4)^(z4⊕z5)^(z5=>z6)=1
(x6+y6+z6) =1
Solving final equation via splitting graph nodes
Passing Polyakov's control
Consider another system
(x1=>x2)^(x2⊕x3)^(x3=>x4)^(x4=>x5)^(x5=>x6)=1
(y1=>y2)^(y2=>y3)^(y3⊕y4)^(y4=>y5)^(y5=>y6)=1
(z1=>z2)^(z2=>z3)^(z3=>z4)^(z4⊕z5)^(z5=>z6)=1
(x1+y2+z3) =1
Here we intend to manage via pass to centre per Helen Mironchick
Passing Polyakov's Control
(x1=>x2)^(x2⊕x3)^(x3=>x4)^(x4=>x5)^(x5=>x6)=1
(y1=>y2)^(y2=>y3)^(y3⊕y4)^(y4=>y5)^(y5=>y6)=1
(z1=>z2)^(z2=>z3)^(z3=>z4)^(z4⊕z5)^(z5=>z6)=1
(x6+y6+z6) =1
Consider another system
(x1=>x2)^(x2⊕x3)^(x3=>x4)^(x4=>x5)^(x5=>x6)=1
(y1=>y2)^(y2=>y3)^(y3⊕y4)^(y4=>y5)^(y5=>y6)=1
(z1=>z2)^(z2=>z3)^(z3=>z4)^(z4⊕z5)^(z5=>z6)=1
(x1+y2+z3) =1
Here we intend to manage via pass to centre per Helen Mironchick
Passing Polyakov's Control





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